Stackless Python and Python 2.x

[Michael Abbott]

aahz at panix.com (Aahz Maruch) wrote in news:9n5d7c$i0o$1 at panix2.panix.com:

> The actual execution frame (the part that stores all the local names) is
> stored on the heap, not on the stack.  

Aha.  I thought it might be something like that.  So the interpreter picks 
up the frame, and (presumably tucked away somewhere safe in the generator 
object) picks up the byte code instruction pointer, and off we go.  Is it 
really as simple as that?