Detecting PyCObjects using type()

[Lenny Hoffman]

Hi Jeff,

I just had to solve the same problem.  I have written an extension module,
but did not know how to export the "type" object for comparison to one
retrieved from the type function.  What I ended up doing was to do a test
like this:

    if str(type(arg1)) == "<type 'PyCObject'>":

One can easily imagine a helper function to perform this test given any type
name:

def isType(obj, typeName):
   return str(type(obj)) == "<type '%s'>" % typeName

Perhaps a simular function exists, but I was unable to find one.

Regards,

Lenny

"Jeff Putsch" <putsch at fiber.mxim.com> wrote in message
news:mailman.990200847.25222.python-list at python.org...
> Howdy,
>
> I would like to be able to do something like this:
>
>    class C:
>       def __init__(self,arg1):
>          if type(arg1) != type(PyCObject):
>             raise AnException
>
> Unfortunately type(PyCObject) is not legal.
>
> If arg1 is a PyCObject, the type(arg1) returns:
>
>    <type 'PyCObject'>
>
> What I can not figure out is what "type(PyCObject)" should be, to make the
> test work. With other types syntax like this works:
>
>    if type(arg1) == type('')
>
> So my question boils down to this: what is the equivalent of "type('')"
when
> using PyCObjects?
>
> Thanks,
>
> Jeff.
>
>
>