Getting all the *files* from a directory -- A better way??

[piet at cs.uu.nl]

>>>>> scarblac at pino.selwerd.nl (Remco Gerlich) (RG) writes:

RG> Or even

RG> dir="a/b/c"
RG> files = [os.path.join(dir, f) for f in os.listdir(dir)
RG>                               if os.path.isfile(f)]

RG> If you do the map() with a list comprehension, why not the filter() as
RG> well.

Perhaps because it would have to be:
                 if os.path.isfile(os.path.join(dir, f))
-- 
Piet van Oostrum <piet at cs.uu.nl>
URL: http://www.cs.uu.nl/~piet [PGP]
Private email: P.van.Oostrum at hccnet.nl