"has" Operator
Guido van Rossum
guido at python.org
Sun Jul 8 08:43:13 EDT 2001
"John Roth" <johnroth at ameritech.net> writes:
> "Paul Sidorsky" <paulsid at home.com> wrote in message
> news:mailman.994543873.6493.python-list at python.org...
> > Roman Suzi wrote:
> >
> > > if hasattr(myobject, "someattribute"):
> > > foo()
> > > else:
> > > bar()
> > > is clean enough, IMHO...
> >
> > Oops, I didn't know about hasattr(). Yes, that certainly does the
> > trick. Though I have to say the syntax is a little odd (what with the
> > quotes), but it's certainly sufficient. Thanks! Sorry to bother
> > everyone.
>
> Not a bother. We learn by watching everyone else ask questions! However,
> the syntax is necessary, since "hasattr" is essentially a dictionary lookup.
Actually, Paul's proposal to write
x has y
instead of
hasattr(x, 'y')
has a nice Pythonic ring to it, and the fact that you have to use
quotes with hasattr() has always bothered me. Too bad I didn't think
of this 10 years ago; right now, I'd say it's too little value for too
much disturbance (a new keyword).
--Guido van Rossum (home page: http://www.python.org/~guido/)
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