Most efficient solution?

[Jay Parlar]

> 
>That will teach me to post without testing. This doesn't work at all - items
>from B are removed from the temporary, unnamed list created for A + B.
Hehe, that's what I thought. At first I just assumed you were right and wondered what I was doing wrong ;-)


>A bit neared the truth would be:
>
>A += B
>map(A.remove, B)
>
>But this doesn't really work, either. Only the first occurrence of each
>token in B is removed.
I was thinking the same thing, you're essentially going to always remove only the elements you add by concatenating the 
two lists together.


>It strikes me that if B is large, it might be quicker to build a re pattern
>from its elements, and match on that, rather than use 'in'. I'll give that a
>bash later.
If you do, cool, if not, no worries. Like I said in the original post, any insight is appreciated.

>Cheers,
>Simon Brunning
>TriSystems Ltd.
>sbrunning at trisystems.co.uk
>
>
>
>
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Jay Parlar
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Software Engineering III
McMaster University
Hamilton, Ontario, Canada

"Though there are many paths
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