Nested List Comprehension

[Greg Ewing]

Burkhard Kroesen wrote:
> 
> Maybe you feel more comfortable with
> multtab = [x*y for x in range(13) for y in range(13)]

But that doesn't produce what he wanted, which
was for multtab[x][y] to be equal to x*y.

But if there were such a thing as dictionary
comprehensions, he could use

  multtab = {(x,y):x*y for x in range(13) 
                         for y in range(13)}

:-)

-- 
Greg Ewing, Computer Science Dept, University of Canterbury,	  
Christchurch, New Zealand
To get my email address, please visit my web page:	  
http://www.cosc.canterbury.ac.nz/~greg