line continuations with backslash

[Bengt Richter]

On 27 Aug 2001 13:44:02 -0700, Paul Rubin <phr-n2001 at nightsong.com> wrote:

>bokr at accessone.com (Bengt Richter) writes:
>>  >>> dis.dis(compile("'123' '456'",'','eval'))
>>            0 SET_LINENO               0
>>            3 LOAD_CONST               0 ('123456')
>>            6 RETURN_VALUE
>>  >>> marshal.dumps(compile("'123' '456'",'','eval'))
>>  'c\x00\x00\x00\x00\x01\x00\x00\x00s\x07\x00\x00\x00\x7f\x00\x00d\x00\x00S(\x01\x00\x00\x00
>>  s\x06\x00\x00\x00123456(\x00\x00\x00\x00(\x00\x00\x00\x00(\x00\x00\x00\x00(\x00\x00\x00\x0
>>  0s\x00\x00\x00\x00s\x01\x00\x00\x00?\x00\x00s\x00\x00\x00\x00'
>>  >>>
>> 
>> The '123' '456' seems to be folded in the tokenizer,
>> not passed on as tokens for a join op.
>
>Yes, that's fine.  But '123456' still takes 6 bytes.  Marshalled as a
>long int, it would take just over 2 bytes (obviously there would be some
>unused bits, but remember that we're actually talking about much longer
>numbers, like 300 digits).

Maybe this?

>>> dis.dis(compile(`long('123' '456')`, '', 'eval'))
          0 SET_LINENO               0
          3 LOAD_CONST               0 (123456L)
          6 RETURN_VALUE