base classes

[Fredrik Stenberg]

On Wed, 22 Aug 2001, Pete wrote:
> One question about classes. I have two classes, both have attribute called
> 'a'
> class a1:
>     def __init__( self ):
>         self.a = 1
> class a2:
>     def __init__( self ):
>         self.a = 2
> class aa( a1, a2 ):
>     def __init__( self ):
>         a1.__init__( self )
>         a2.__init__( self )
>
> AA = aa()
> print AA.__dict__
> --------------------------------------
> this code prints:
> {'a': 2}
>
> but if I change self.a to self.a_ in class a1:
> class a1:
>     def __init__( self ):
>         self.a_ = 1
> class a2:
>     def __init__( self ):
>         self.a = 2
> class aa( a1, a2 ):
>     def __init__( self ):
>         a1.__init__( self )
>         a2.__init__( self )
>
> AA = aa()
> print AA.__dict__
> ------------------------------------------
> I got:
> {'a_': 1, 'a': 2}
>
> The question is: cannot 2 base classes have the same attributes? What is
> workaround?
>

I'm not sure this is what you want but you can always prefix the attr
with "__" to get name mangling...

Check out,
http://www.python.org/doc/current/tut/node11.html#SECTION0011600000000000000000
(section 9.6 in the python tutorial)

Example;

class a1:
    def __init__( self ):
        self.__a = 1

    def printa1(self):
        print self.__a

class a2:
    def __init__( self ):
        self.__a = 2

    def printa2(self):
        print self.__a

class a3:
    def __init__( self ):
        self.a = 3

    def printa3(self):
        print self.a

class aa( a1, a2,a3 ):
    def __init__( self ):
        a1.__init__( self )
        a2.__init__( self )
        a3.__init__( self )

AA = aa()
-----------------------------
>>> AA.printa1()
1
>>> AA.printa2()
2
>>> AA.a
3


/fredriks