Newbie lists question

[Emile van Sebille]

Does something like this feel better?

>>> d = {}
>>> for i in (1,2,3,2,3,4,3,4,5):
 d[i] = d.setdefault(i,[])
 d[i].append(i)

HTH,

--

Emile van Sebille
emile at fenx.com

---------


"Wolfe Maykut" <wolfe at spam.me.not> wrote in message
news:3B785215.19D583C8 at spam.me.not...
>     Hi.  I'm trying to create a list on the end of a dictionary.   I'd
> like to have a single loop, but since the dictionary is dynamically
> generated it appears as if I have to test to see if the key is around
> and then treat each case differently in order to initialize the loop.
> It looks ugly.  Is there a nicer way of doing this that I'm missing?
>
>     Thanks,
>
>                 --Wolfe
>
> #!/usr/bin/python
>
> import os, time, glob, string
>
> backupdir = glob.glob("/netbackups/.disks/disk*/*.out")
>
> prefixes = {}
>
> for file in backupdir:
>     filename = string.split(file, '/')[-1]
>     prefix = string.split(filename,'.')[0]
>     if prefixes.has_key(prefix):                     # This is the loop
> I think is tres' ugly
>        prefixes[prefix].append(file)
>     else:
>         prefixes[prefix] = []
>         prefixes[prefix].append(file)
>
> for key in prefixes.keys():
>     print key
>     for file in prefixes[key]:
>         st = os.stat(file)
>         format = time.strftime("%b-%d-%Y-%H:00", time.localtime(st[8]))
>         print "  ", file, format
>