Formatting RFC 822 date

[Matthew Dixon Cowles]

On 3 Apr 2001 18:25:45 GMT, brey at ductape.net <brey at ductape.net> wrote:

>Is there a module that I'm missing that will take a time tuple and output the
>proper RFC 822 date string?

Ed,
I'll append what I do in Swallow. I think it's right.

Regards,
Matt


def getRfc822Date():
  # Can't use the strings from the time module since they
  # vary by locale and RFC822 (amended by RFC1123) requires
  # English.

  dayNames=("Mon","Tue","Wed","Thu","Fri","Sat","Sun")
  monthNames=("","Jan","Feb","Mar","Apr","May","Jun","Jul","Aug", \
              "Sep","Oct","Nov","Dec")

  timeTuple=time.localtime(time.time())
  timeStr=dayNames[timeTuple[6]]+", "+str(timeTuple[2])+" "+ \
    monthNames[timeTuple[1]]+" "+str(timeTuple[0])+" "

  timeStr=timeStr+time.strftime("%H:%M:%S ",timeTuple)
  
  if timeTuple[8]<>0:
    zoneSecs=time.altzone
  else:
    zoneSecs=time.timezone

  zoneAbsSecs=abs(zoneSecs)
  zoneMins=zoneSecs/60
  zoneHours=int(zoneMins/60) # Actually already integer division
  zoneLeftoverMins=zoneMins-zoneHours*60

  if zoneSecs>0:
    timeStr=timeStr+"-"
  timeStr=timeStr+"%02i%02i " % (zoneHours,zoneLeftoverMins)

  timeStr=timeStr+"("+time.tzname[timeTuple[8]]+")"
  return timeStr