string->list->string

[Courageous]

On Mon, 23 Apr 2001 18:36:48 -0600, Bjorn Pettersen <BPettersen at NAREX.com> wrote:

>>>> x = [1,2,3]
>>>> str(x)
>'[1, 2, 3]'
>>>> eval(str(x))
>[1, 2, 3]

Not getting it: I want

s = "abc"
l = list(s)
<something>(l)
"abc"

Where something is some expression. The worst part here is that sometime in
the last year, I've asked this very same question before. *IRK* Is this in the FAQ?
It outta be.

>>>> s = "a!b%c^"
>>>> import string
>>>> t = string.maketrans(s,s)
>>>> s.translate(t, "!%^")
>'abc'

Hrm. I read the documentation for string.maketrans() and string.translate() just now.
I don't get it. The documentation doesn't make this clear, and I don't understand
from your example what's going on. While I can see that it works, I don't get the
basic principle. I would think a maketrans of s,s would just translate one character
to the same character.

???

C//