Is there a more elegant way to do this?
Opinderjit
bhellao at my-deja.com
Wed Sep 13 17:45:31 EDT 2000
Will this work for you?
def runningReport(self):
cnt = self.counters[:] # make a copy
cnt.sort()
indx = cnt[len(cnt)-5:] # get the 5 largest
for i in indx:
print self.counters(cnt[i])
In article <8poglt$10fq$1 at news.rchland.ibm.com>,
"Larry Whitley" <ldw at us.ibm.com> wrote:
> Here's the problem:
>
> I have a list of counters that will have a wide variety of different
values
> in them. At intervals while the program runs, I will print out the
indexes
> of the counters with the five largest counts. The counters are in a
list
> identified below as self.counters. Here's my inelegant way of doing
it.
>
> def runningReport(self): # a method of a larger class
> temp = [] # to make sure that temp is not just another reference
to
> self.counters
> temp = temp + self.counters # there are 100 individual counts in
> self.counters
> temp.sort()
> temp.reverse() # now largest value is first
> temp2 = [] # for the result
> for i in range( 5 ):
> temp2.append( self.counters.index( temp[i] ) # find the index
of the
> next (largest) counter and store it in temp2
> print temp2
>
> Surely there is a better way....
>
> Larry
>
>
--
Java who?
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