super - is (should) it (be) a reserved word?

[Michal Wallace]

On Mon, 9 Oct 2000, Grant Edwards wrote:

> >Why do you need that? Calling a method of a class 
> >climbs the hierarchy for you, all the way up to where
> >the method was first defined or last overridden.
> 
> The example I most often run into is in an __init__ method
> where I want to initialize the features my subclass is adding
> and then pass control and the remaining arguments on up to the
> __init__ method one layer up.  The "super" that I want access
> to is the parent of the class containing the reference to
> "super", not the parent of the class of "self".

I see. I was thinking that .super would be a class member,
not an instance member. If you define it like so:


class Dessert:
    def __init__(self):
        print "dessert!"

class Pie(Dessert):
    super = Dessert
    def __init__(self):
        print "pie is a..."
        Pie.super.__init__(self)

class BananaCremePie(Pie):
    super = Pie
    def __init__(self):
        print "banana creme pie is a..."
        BananaCremePie.super.__init__(self)


then:

>>> weapon = BananaCremePie()
banana creme pie is a...
pie is a...
dessert!

It's not exactly perfect, but there you go..

you could also call it __super and then you don't have to put the
classnames in the __init__ (because python does it for you for
variables starting with [and not ending with] double underscores):


class Pie(Dessert):
    __super = Dessert
    def __init__(self):
        print "pie is a..."
        self.__super.__init__(self)

class BananaCremePie(Pie):
    __super = Pie
    def __init__(self):
        print "banana creme pie is a..."
        self.__super.__init__(self)


Cheers,

- Michal
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