Alan Gauld wrote: > Now assuming the bytes are integers making up the > digits you can just multiply and add succesive digits > by successive powers of 10. > > Thus for 1,2,3,4: > > digits = (1,2,3,4) > > m,n = 1,0 > for i in (1,2,3,4): > n = n + i*m > m = 10 * m assuming 3.3-bit bytes, right? </F>