Eval the caller within a method?
Franz GEIGER
fgeiger at datec.at
Sat Oct 21 05:20:32 EDT 2000
I wonder if in Python there is a possibility to evaluate the method which
called a method within that method like it is in Perl.
This would prevent me from having to write code like
logIt = TLog("Callers name")
logIt("Some diagnostics");
(printing:
"'Callers name': Entered. "
"Callers name': Some diagnostics"
)
because TLog() could figure out which method called it.
Any ideas?
Best regards
Franz GEIGER
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