Isn't re.findall supposed to find all?
June Kim
junaftnoon at nospamplzyahoo.com
Fri Nov 10 18:31:57 EST 2000
Well, I forgot the old rule "Longest match possible."
It worked perfectly with this:
>>> z
'[abcdefrdofhd]kdeioslkdfj[sdkfj]'
>>> p=re.compile('\[[^\[]*\]')
>>> re.findall(p,z)
['[abcdefrdofhd]', '[sdkfj]']
But another problem emerged. What if the brackets were
longer than one character? for example:
z='this is yet another start of a sting end but never start an end'
opening bracket : "start"
closing bracket : "end"
What I want to get is,
re.findall(p,z) == ['[start of a string end]','[start an end]']
How should I render the regular expression?
Thanks in advance
---------
June
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