retrieving from list
Courageous
jkraska1 at san.rr.com
Mon May 29 16:48:49 EDT 2000
> def func(arg):
> a = []
> a.append('foo')
> b = []
> b.append('bar')
> a.append(b)
> # now I have a = ['foo', ['bar']]
> return a[arg][arg]
>
> The last line is where the problem lies. How can 'arg' be able to refer to
> 'foo' or 'bar'? Should 'arg' be a string of comma seperated values which
> would be parsed within the function in order to refer to the proper member
> of the list? For example, '0' for 'foo' and '0,0' for 'bar'?
>
> Any ideas to solve this little problem would be much appreciated,
You need to read about tuples, I think:
def makelist():
a=[]
a.append('foo')
b=[]
b.append('bar')
a.append(b)
return a
def get(mylist,tup):
item=mylist
for i in tup: item=item[i]
return item
def test():
mylist = makelist()
item = get ( mylist, (0,) )
print item
item = get ( mylist, (1,0) )
print item
>>> import f
>>> f.test()
foo
bar
>>>
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