Converting strings to hex

[Kris J. Zaragoza]

On Thu, 18 May 2000 19:24:41 -0700, emile at fenx.com <emile at fenx.com> wrote:
>As long as we're contributing methods, I use this:
>
>def hta(s, padlen=1):
>    """ hta(string) returns a hex repr of string"""
>    if not s:
>        return ""
>    elif type(s)<>type("string"):
>        raise "argument should be of type string"
>    elif len(s)<padlen:
>        while len(s)<padlen:
>            s = '\000' + s
>    h = ""
>    for c in s:
>        h = h + '%2x' % ord(c)
-------------------^

This formatting string is going to return a space-padded number.  If
that's what you're looking for, great.  I'm accustomed to getting
zero-padded numbers, where "\001" would be represented as "01" instead
of " 1".  For zero-padding, you need to use the format string "%02x"
or, "%02X" if you want upper-case letters (A-F).

>    return h
>
>Emile van Sebille
>emile at fenx.com
>
>
>> It must be something in the air. I also needed this yesterday and a
>> DejaNews search yielded this function from Michael Wallace.
>> 
>> def hexify(binaryString):
>>     result = ""
>>     for i in binaryString:
>>         result = result + string.zfill(hex(ord(i))[2:],2)
>>     return result
>> 
>> Jay
>> 
>> 
>> -- 
>> http://www.python.org/mailman/listinfo/python-list
>>
>


-- 
Kris J. Zaragoza           | "Unfortunately, most people can't out-think a
kzaragoza at mediaone.net     | grapefruit."  --Jon Bodner