will python 3000 break my code?

[Daniel Berlin]

>>>>> "FL" == Fredrik Lundh <effbot at telia.com> writes:

   >> | 3. be impossible to identify by automatic tools.  | Tim's excellent
   >> checkappend.py can spot many | cases, but not all.
   >>  Actually, this isn't true (that it's impossible).  If you really like,
   >> i'll take a few days of my spring break and write one guaranteed to
   >> catch every single case.

   FL> how about this one:

   |     foo = list.append
   |     for bar in range(100):
   |         foo(bar, bar, bar)


__name__ of foo will be append and type(foo.__self__) will be list
I had already planned on checking this.

   FL> or this one:

   |     class Foo:
   |         def __init__(self):
   |             self.setup()
   |             self.add = self.list.append
   |         def setup(self):
   |             self.list = []

   |     foo = Foo()
   |     foo.add(bar, bar, bar)

It still has the same pattern in the bytecode.
foo.add.__name__ will be append
type(foo.add.__self__) will be list.

--Dan
   FL> </F>