SV: Python Productivity over C++

[Emile van Sebille]

I think I've got this working so that sub-classed
instances can be compared to subclassed references.

----- Original Message -----
From: Huaiyu Zhu <hzhu at knowledgetrack.com>
<snip>
>
> Cool!  Things always look easier in python. :)
>
> Now only if somebody could enhance that to check inherited
methods too (the
> "more general case").  That is, if a method is not found,
go recursively
> into the superclasses.  The following example is not
correct at the moment:
>
<snip>
> --
> Huaiyu Zhu
hzhu at users.sourceforge.net
> Matrix for Python Project
http://MatPy.sourceforge.net
> --
> http://www.python.org/mailman/listinfo/python-list
>


import types

def meths(items, meths=None):
  if meths == None:
    meths = {}
  for obj in items:
    for k, v in obj.__dict__.items():
      if type(v) == types.FunctionType:
        meths[k]=None
  return meths

def bases(obj, items=None):
  if items == None:
    items = []
  for b in getattr(obj, '__bases__', []):
    bases(b, items)
    items.append(b)
  if type(obj) == types.ClassType:
    items.append(obj)
  return items


def verify_class (Reference, Instance):
  r_meths = meths(bases(Reference))
  i_meths = meths(bases(Instance))

  for meth in r_meths.keys():
    if not i_meths.has_key(meth):
      print "Method %s not supported" % meth


Portions/ideas taken from both Kevin Jacobs
and from David Bolen.

Emile van Sebille
emile at fenx.com
-------------------