getting a URL

[johnvert at my-deja.com]

Hello,

As an exercise I'm trying to write a simple cgi script that will get the
source code of an html file and echo it to the screen.  Here's what I
have:

import cgi, urllib

(snip)

		url = urllib.urlopen("http://www.server.org/foo.html")
		print "<pre>"
		print cgi.escape(url.read()),
		print "</pre>"

But nothing is printed.  The problematic line seems to be:

url = urllib.urlopen("http://www.server.org/foo.html")

But the URL I gave it in the actual program is correct.  I tried a few.
If I run this on the shell (it's meant to be a cgi) it raises IOError
sayin 'network unreachable'.  What could be wrong?  Also, why does
execution stop at:

      print "<pre>"

Why isn't the rest (print "</pre>" among others) printed?

Thanks,
 -- John


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