win32Service.OpenService not working
kellyk at my-deja.com
kellyk at my-deja.com
Tue Jun 6 18:12:32 EDT 2000
In article <8hggdu$4fa$1 at nnrp1.deja.com>,
tiddlerdeja at my-deja.com wrote:
> However, if I try to get a service with a space in the name, I get an
> error:
> >>> h = win32service.OpenService(hscm, "Windows installer",
> win32service.SERVICE_ALL_ACCESS)
As has been pointed out there is a descriptive name and an internal
name. To find out both names (and other info; see docs) for all services
use:
>>> import win32service
>>> SC= win32service.OpenSCManager("", None,
win32service.SC_MANAGER_ALL_ACCESS)
>>> services= win32service.EnumServicesStatus(SC)
>>> print services
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