parameter undefined in procedure

[David Smith]

Moshe Zadka wrote:

> The "lambda" expression defines a function. Inside it, the only locals
> are the parameters (since there can be no assignments inside a lambda),
> so in your case the only local is "x". "dictionary" isn't a global,
> and it isn't a builtin (thank God!) either. If you want your lambda
> expression to see it, you have to explicitly define it:
> 
> return map(lambda x, dictionary=dictionary: dictionary.get(x, "default"),
>             list)

Thank you for the clarification.

> If you think this is god-awful ugly, you're right. Why not code it
> as an explicit loop?

Lisp hangover, I suppose.  Which is also the reason lambda is in Python,
no?

	David Smith