regsub backreference question

[Michael Esveldt]

I'm trying to figure out how back referencing works in python's regsub 
module. I thought the following code would simply double the string 
"foo" but it's just returning "foo".

regsub.sub(r"(.*)", r"\1\1", "foo")

What am I doing wrong here?

thanks in advance,
Michael
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dante at oz.net - Michael Esveldt - #FightThePower on Openprojects