The Opposite of list(a,b,c)?

[Daniel Berlin]

On Fri, 14 Apr 2000, Andrew P. Jewell wrote:

<snip>
> def func(SearchTerm):
>   <...>
>     retval = []
>     for keyval in (dtnA.keys()):
>         mtch = re.search(patSrchTrm, keyval)
>         if mtch:
>             retval.append(UNLIST(dtnA[keyval]))

Change this to:

if mtch:
	for value in dtnA[keyval]:
		retval.append(value)



> 
> I want to end up with just a list of matching values from the dictionary,
> ala:
>     ['val1, val2', 'val3, val4']
> 
> But I can only get a list of lists: [[val1,val2],[val3,val4]] - which
> makes perfect sense based on how I'm doing it - but I don't WANT a list
> of lists!  Is there anyway to do this?  I don't really want to tuple-ize
> my dictionary since it's attached to its list values in other ways.  It
> seems ugly to have to iterate my dictionary value list to UN-list them
> manually - and the repr deal is REALLY ugly. What am I missing??  Thanks
> for any help!

Okay, you don't want to iterate?
Let something else iterate for you:
>>> def delist(x, retval):
...     import types
...     for a in x:
...             if type(a)==types.ListType:
...                     delist(a,retval)
...             else:
...                     retval.append(a)
...     return retval
...
>>> delist([5,6],[])
[5, 6]
>>> delist([5,6,[5,6]],[])
[5, 6, 5, 6]
>>> delist([5,6,[5,6],[5,[5,5]]],[])
[5, 6, 5, 6, 5, 5, 5]
>>>
etc
--Dan
> 
> Andy
>