list.without()?

[Stidolph, David]

so ...

def without(source, element):
  while element in source:
    source.remove(element)  

Is that what you are looking for?  It would help if I had read the earlier
posts!  :)

-----Original Message-----
From: Christian Tismer [mailto:tismer at appliedbiometrics.com]
Sent: Tuesday, November 16, 1999 11:15 AM
To: Magnus L. Hetland
Cc: python-list at python.org
Subject: Re: list.without()?




"Magnus L. Hetland" wrote:
> 
> "Mike Fletcher" <mcfletch at vrtelecom.com> writes:
> 
> > Well...
> >
> > def without( source, element):
> >       temp = source[:]
> >       while temp:
> >               try:
> >                       temp.remove( element )
> >               except:
> >                       break
> >       return temp
> 
> Whoa!
> 
> Why on *earth* would you use a while/try/break-combination? IMO a much
> more natural solution would be:
> 
> def without(source, element):
>     result = source[:]
>     if element in result:
>         result.remove(element)
>     return result

But that would be wrong.
"Without" means "there is no such object in it", while list.remove
removes the first occourance of an object.

Mike's implementation appears to be very cheap, since through
the try..except clause, he can combine removal with test
for existance.

ciao - chris

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