how to split the contain of retr (using poplib module)

[Piers Lauder]

muniff at yahoo.com (Ahmad Munif) wrote:
 >
 > i'm using poplib module to connect to pop3 server.
 > i can retrieve mail with retr mothode.
 > but i don't know, how to split the contain of mail,
 > so, i can get the value of mail, such as: To,From,body message.
 > how to split it ?

The `retr' method returns three values: (comment, lines, octets)

You can ignore `comment' and `octets', the interesting one
is `lines', which is a list of message lines with trailing
<CR><NL> combinations stripped.

Here's an example of parsing `lines' into something useful:

	import mimetools, string, StringIO

	lines.append('')	# last newline
	data = string.join(lines, '\n')
	mime = mimetools.Message(StringIO.StringIO(data), 1)

Read the mimetools documentation for how to get at the header
components in the `mime' instance.