Keyword calling gotcha ?

[Alex]

Yeah, I think the problem is that you're passing a dictionary rather
than the same set of arguments to A.__init__.

>>> def keyword_usage_example (**parms):
    	print parms
    	keyword_usage_example (parms)

... ... ... >>> 
>>> keyword_usage_example (a=1,b=2) 
{'b': 2, 'a': 1}
Traceback (innermost last):
  File "<stdin>", line 1, in ?
  File "<stdin>", line 3, in keyword_usage_example
TypeError: too many arguments; expected 0, got 1
>>> 

There's probably a clean way to deal with this, but I don't know it.
Here is a messy way:

def alternative_keyword_usage_example (**parms):
    if parms.has_key ('key_word_dictionary'):
        parms = parms ['key_word_dictionary']
    print parms
    alternative_keyword_usage_example (key_word_dictionary = parms)

alternative_keyword_usage_example (a = 1, b = 2)

I think the guys running my newsgroup server will get pissed off if I
show you the output...

See you.
Alex.