ANN: Stackless Python 0.2

[G. David Kuhlman]

Tim Peters (tim_one at email.msn.com) wrote:

> 
> That's mostly true today too:  Python threads run serially now, one at a
> time, and if a thread calling out to C doesn't release the global lock no
> other thread will run until it returns.
> 

I'll bite. How *does* a thread that calls out to C release the global
lock?

Would it have to do this thingy that is at the beginning of the
interpreter loop in python/ceval.c?

    if (PyThreadState_Swap(NULL) != tstate)
        Py_FatalError("ceval: tstate mix-up");
    PyThread_release_lock(interpreter_lock);

Would this work? or would it screw up the interpreter?

Is there a way to do this in a Python script *before* it calls out
to C.

Is there an approved solution to this problem?


  - (mystified) Dave