Name of function within the function?

[Darrell]

import sys, string, os

def myDirExcept(howFarBack):
        """
        Get the directory of the module running at "howfarBack "
        in the stack frames
        This value is compiled into the .pyc file
        This can be a problem.
        This name will change depending on where python was run from
        when the pyc file was created
        Unix can store a relative path
        Windows stores an absolute path
        """
        try:
                raise ZeroDivisionError
        except ZeroDivisionError:
                f = sys.exc_info()[2].tb_frame

        for i in range(howFarBack):
                f = f.f_back

        t = f.f_code
        fname = t.co_filename
        p = string.split(fname, os.sep)
        fname = string.join(p[:-1], os.sep)
 print t.co_name, fname
        return fname


myDirExcept(0)

###################################

E:\ace\v2\code\comp>junk2.py
myDirExcept E:\ace\v2\code\comp


--
--Darrell
Dula, Debbie (EXCHANGE:RICH2:2C25) <violet at americasm01.nt.com> wrote in
message news:377B8C2F.80F44F9 at americasm01.nt.com...
> I've looked and looked, but can't find the answer to this ... I'm
> sure it's right in front of me ...
>
>
> I want the current function's name to be output in my error
> messages, but can't figure out how a function can get its own name
> (without already knowing it).  For example,
>
> def f1():
> print "Error in function", f1.__name__
>
> is not really useful for what I need as I might as well print "Error
> in function f1".  Is there any generic way I can get the current
> function's name?
>
> Thanks,
> Debbie