Converting a string to a tuple

[Bruce Huzyk]

I will now take this opportunity to revise my original post.
I wish to convert a string to a tuple.
My sample string should have been:
	s = '(1, "abc\\tef", 2)' 
instead of:
	s = '(1, "abc\\def", 2)' 

The problem is that the \\t part of the string gets expanded to a \011

Only the eval(string.replace(s, '\\', '\\\\')) seems to do the job. Any
comments?

sample code:
>>> s = '(1, "abc\\tef", 2)' 
>>> eval(s)
(1, 'abc\011ef', 2)

s = '(1, "abc\\tef", 2)' 
>>> eval(string.replace(s, '\\', '\\\\'))
(1, 'abc\\tef', 2)


>>> s = '(1, "abc\\tef", 2)' 
>>> eval(s, {"__builtins__": {}})
(1, 'abc\011ef', 2)


>>> s = '(1, "abc\\tef", 2)' 
>>> r = rexec.RExec()
>>> s = '(1, "abc\\tef", 2)' 
>>> r = rexec.RExec()
>>> r.r_eval(s)
(1, 'abc\011ef', 2)



Fredrik Lundh <fredrik at pythonware.com> wrote in article
<00f501be857f$ff636f40$f29b12c2 at pythonware.com>...
> Charles G Waldman wrote:
> > If you're concerned about safety (the "eval" could be evaluating any
> > Python code, possibly a hazard if the string is coming from user
> > input) then you don't want to use eval at all.
> 
> try:
> 
>     result = eval(string, {"__builtins__": {}})
> 
> or:
> 
>     import rexec
>     r = rexec.RExec()
>     result = r.r_eval(string)
> 
> </F>
> 
>