[Python-ideas] A "within" keyword

[Robert Vanden Eynde]

Classes Provide already some features of a namespace :

class cool_namespace:
    A = 8

    @staticmethod
    def f():
        return "yo"

    @staticmethod
    def g():
        return (1 + cool_namespace.A) * cool_namespace.f()

And if you're tired of writing @staticmethod, you can write a class
decorator "namespace" :

@namespace
class cool_namespace:
    A = 8

    def f():
        return "yo"

    def g():
        return (1 + cool_namespace.A) * cool_namespace.f()

And I think this decorator already exists somewhere.

Le sam. 9 juin 2018 à 10:21, Steven D'Aprano <steve at pearwood.info> a écrit :

> On Fri, Jun 08, 2018 at 03:07:28PM -0700, Michael Selik wrote:
>
> > You can use ``eval`` to run an expression, swapping in a different
> globals
> > and/or locals namespace. Will this serve your purpose?
> >
> > In [1]: import types
> > In [2]: ns = types.SimpleNamespace(a=1)
> > In [3]: eval('a', ns.__dict__)
> > Out[3]: 1
>
> The public API for getting an object namespace is vars(ns).
>
> But why would we write eval('a', vars(ns)) instead of getattr(ns, 'a')
> or even better just ns.a? Is your Python code too fast and you need to
> slow it down? *wink*
>
> eval and exec are useful when the code you want to run needs to be
> constructed at runtime. Its not generally useful when you know what you
> want ahead of time as in your example above.
>
>
>
> --
> Steve
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