[Python-ideas] Delayed Execution via Keyword

Abe Dillon abedillon at gmail.com
Fri Feb 17 15:41:16 EST 2017


>
> Couldn't the same thing be true of delayed if it is always followed by a
> colon?


No. Because there are other reasons you'd follow the variable `delayed`
with a colon:

>>> delayed = 1
>>> d = {delayed: "oops!"}

My earlier proposal (using unpacking syntax) doesn't work for the same
reason.

On Fri, Feb 17, 2017 at 2:31 PM, Joseph Hackman <josephhackman at gmail.com>
wrote:

> Couldn't the same thing be true of delayed if it is always followed by a
> colon?
>
> I.e.
> delayed=1
> x= delayed: slow_function()
> print(delayed) # prints 1
>
> -Joseph
>
> On Feb 17, 2017, at 2:39 PM, Mark E. Haase <mehaase at gmail.com> wrote:
>
> On Fri, Feb 17, 2017 at 1:55 PM, Joshua Morton <joshua.morton13 at gmail.com>
> wrote:
>
>> but I'm wondering how common async and await were when that was proposed
>> and accepted?
>
>
> Actually, "async" and "await" are backwards compatible due to a clever
> tokenizer hack. The "async" keyword may only appear in a few places (e.g.
> async def), and it is treated as a name anywhere else.The "await" keyword
> may only appear inside an "async def" and is treated as a name everywhere
> else. Therefore...
>
>     >>> async = 1
>     >>> await = 1
>
> ...these are both valid in Python 3.5. This example is helpful when
> proposing new keywords.
>
> More info: https://www.python.org/dev/peps/pep-0492/#transition-plan
>
>
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