[Python-ideas] os.path.abspath - optional startdir argument

[Juancarlo Añez]

On Thu, Jul 24, 2014 at 9:24 PM, Ryan <rymg19 at gmail.com> wrote:

> Instead, though, you'd do:
>
> f = (Path(_file__) / 'app.conf').open()
>

Indeed, that solves the "right place in the module dependency hierarchy"
thing, and it even has an "econding=" kwarg!

I hadn't paid attention to it. Sorry.

Problem solved!

Thanks!


-- 
Juancarlo *Añez*
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