[Python-Dev] [Python-compilers] Developing a Python JIT and have troubld

[Siu Kwan Lam]

I have never tried PEP0523 before so I have just did a quick look and
pushed what I got to https://github.com/sklam/etude_py36_custom_jit.

If you run
https://github.com/sklam/etude_py36_custom_jit/blob/master/test.py, you
should get the following printouts:

Hello
Hey
Yes
** myjit is evaluating frame=0x10c623048 lasti=-1 lineno=10
Enter apple()
** myjit is evaluating frame=0x7f9a74e02178 lasti=-1 lineno=16
Enter orange()
Exit orange()
Exit apple()
** myjit is evaluating frame=0x10c460d48 lasti=-1 lineno=27

The frame is different for each method.

Can you try your implementation with my test so we can compare?

On Thu, Mar 30, 2017 at 11:46 PM Yuheng Zou <zouyuheng1998 at gmail.com> wrote:

I am building a Python JIT, so I want to change the interp->eval_frame to
my own function.

I built a C++ library which contains EvalFrame function, and then use dlopen
 and dlsym to use it. It looks like this:

extern "C" PyObject *EvalFrame(PyFrameObject *f, int throwflag) {
    return _PyEval_EvalFrameDefault(f, throwflag);}

I added following code to Python/pylifecycle.c at function
_Py_InitializeEx_Private(Python version is 3.6.1):

void *pyjit = NULL;
pyjit = dlopen("../cmake-build-debug/libPubbon.dylib", 0);if (pyjit != NULL) {
    interp->eval_frame = (_PyFrameEvalFunction)dlsym(pyjit, "EvalFrame");
    //interp->eval_frame = _PyEval_EvalFrameDefault;}

Then something strange happened. I used LLDB to trace the variables. When
it ran at EvalFrame, the address of f pointer didn't change, but f->f_lineno
 changed.

Why the address of the pointer didn't change, but the context change?

I am working on Mac OS X and Python 3.6.1. I want to know how to replace
_PyEval_EvalFrameDefault in interp->eval_frame with my own function.
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-- 
Siu Kwan Lam
Software Engineer
Continuum Analytics
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