[Python-Dev] operator precedence of __eq__, __ne__, etc, if both object have implementations
Greg Ewing
greg.ewing at canterbury.ac.nz
Wed Sep 23 06:27:21 CEST 2009
Willem Broekema wrote:
> The AND above (which I uppercased) is subtle but important. In the "x
> op y" case with y being of a subclass of the class of x, if there is
> no class in between x and y (excluding x, including y) that overrides
> the __rop__ method, then y,__rop__(x) is *not* tried before
> x.__op__(y).
How does this work at the C typeslot level, where
there are no __rop__ methods?
--
Greg
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