[Python-Dev] yield * (Re: Missing operator.call)

[Greg Ewing]

Guido van Rossum wrote:
> We already have yield expressions and they mean something else...

They don't have a "*" in them, though, and I don't
think the existing meaning of yield as an expression
would carry over into the "yield *" variant, so there
shouldn't be any conflict.

But if you think there will be a conflict, or that the
similarity would be too confusing, maybe the new
construct should be called something else. I'm
open to suggestions.

-- 
Greg