[Python-Dev] PEP 203 Augmented Assignment

[M.-A. Lemburg]

Skip Montanaro wrote:
> 
> 
>     >> Another important reason is that in cases like
>     >>
>     >> a[long_and_expensive_call()] = a[long_and_expensive_call()] + 1
> 
>     M-A> Dito for this one:
> 
>     M-A> i = long_and_expensive_call()
>     M-A> a[i] = a[i] + 1
> 
> Only if you know that long_and_expensive_call() has no side effects!

If it does, then you'll have to write the long version anyway,
if it doesn't I don't see a problem, if you don't know then
you shouldn't use the function anyway ;-))

-- 
Marc-Andre Lemburg
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