[Python-checkins] cpython: Issue #26130: Remove redundant variable 's' from Parser/parser.c
berker.peksag
python-checkins at python.org
Sun Mar 27 17:43:31 EDT 2016
https://hg.python.org/cpython/rev/a90f5e2b7160
changeset: 100775:a90f5e2b7160
user: Berker Peksag <berker.peksag at gmail.com>
date: Mon Mar 28 00:45:28 2016 +0300
summary:
Issue #26130: Remove redundant variable 's' from Parser/parser.c
Patch by Oren Milman.
files:
Parser/parser.c | 9 ++++-----
1 files changed, 4 insertions(+), 5 deletions(-)
diff --git a/Parser/parser.c b/Parser/parser.c
--- a/Parser/parser.c
+++ b/Parser/parser.c
@@ -140,21 +140,20 @@
int n = g->g_ll.ll_nlabels;
if (type == NAME) {
- const char *s = str;
label *l = g->g_ll.ll_label;
int i;
for (i = n; i > 0; i--, l++) {
if (l->lb_type != NAME || l->lb_str == NULL ||
- l->lb_str[0] != s[0] ||
- strcmp(l->lb_str, s) != 0)
+ l->lb_str[0] != str[0] ||
+ strcmp(l->lb_str, str) != 0)
continue;
#ifdef PY_PARSER_REQUIRES_FUTURE_KEYWORD
#if 0
/* Leaving this in as an example */
if (!(ps->p_flags & CO_FUTURE_WITH_STATEMENT)) {
- if (s[0] == 'w' && strcmp(s, "with") == 0)
+ if (str[0] == 'w' && strcmp(str, "with") == 0)
break; /* not a keyword yet */
- else if (s[0] == 'a' && strcmp(s, "as") == 0)
+ else if (str[0] == 'a' && strcmp(str, "as") == 0)
break; /* not a keyword yet */
}
#endif
--
Repository URL: https://hg.python.org/cpython
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