[Python-checkins] r56363 - python/branches/release25-maint/Doc/lib/libitertools.tex
raymond.hettinger
python-checkins at python.org
Sat Jul 14 13:31:35 CEST 2007
Author: raymond.hettinger
Date: Sat Jul 14 13:31:35 2007
New Revision: 56363
Modified:
python/branches/release25-maint/Doc/lib/libitertools.tex
Log:
Backport 56345
Modified: python/branches/release25-maint/Doc/lib/libitertools.tex
==============================================================================
--- python/branches/release25-maint/Doc/lib/libitertools.tex (original)
+++ python/branches/release25-maint/Doc/lib/libitertools.tex Sat Jul 14 13:31:35 2007
@@ -117,7 +117,7 @@
Make an iterator that drops elements from the iterable as long as
the predicate is true; afterwards, returns every element. Note,
the iterator does not produce \emph{any} output until the predicate
- is true, so it may have a lengthy start-up time. Equivalent to:
+ first becomes false, so it may have a lengthy start-up time. Equivalent to:
\begin{verbatim}
def dropwhile(predicate, iterable):
@@ -474,8 +474,8 @@
return izip(mapping.iterkeys(), mapping.itervalues())
def nth(iterable, n):
- "Returns the nth item or raise IndexError"
- return list(islice(iterable, n, n+1))[0]
+ "Returns the nth item or raise StopIteration"
+ return islice(iterable, n, None).next()
def all(seq, pred=None):
"Returns True if pred(x) is true for every element in the iterable"
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