[issue39500] Document PyUnicode_IsIdentifier() function

[Serhiy Storchaka]

Serhiy Storchaka <storchaka+cpython at gmail.com> added the comment:

It is not convenient to check the result for error. After we remove support of old PyUnicode API, PyUnicode_IsIdentifier() will be always succeeded.

Note that PyUnicode_IsIdentifier() still can crash if you pass a non-PyUnicode object or NULL. It is a prerequisite of this function that the argument must be a PyUnicode object. Add just yet one condition: it must be a ready PyUnicode object.

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<https://bugs.python.org/issue39500>
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