[issue37455] asyncio.run() error related to finalizing async generators
Sam Frances
report at bugs.python.org
Sun Jun 30 19:55:50 EDT 2019
Sam Frances <sam at samfrances.uk> added the comment:
Apologies for the stray unused function in the example. It should have read:
```
import asyncio
async def count():
try:
i = 0
while True:
yield i
i += 1
finally:
print("count() cleanup")
async def double(source):
try:
async for n in source:
yield n * 2
finally:
print("double() cleanup")
async def main():
async for i in double(count()):
if i > 10:
return
print(i)
asyncio.run(main())
```
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<https://bugs.python.org/issue37455>
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