[issue32308] Replace empty matches adjacent to a previous non-empty match in re.sub()

[Matthew Barnett]

Matthew Barnett <python at mrabarnett.plus.com> added the comment:

Consider re.findall(r'.{0,2}', 'abcde').

It finds 'ab', then continues where it left off to find 'cd', then 'e'.

It can also find ''; re.match(r'.*', '') does match, after all.

It could, in fact, an infinite number of ''.

And what about re.match(r'()*', '')?

What should it do? Run forever? Raise an exception?

At some point you have to make a decision as to what should happen, and the general consensus has been to match once.

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<https://bugs.python.org/issue32308>
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