[issue29297] python3 open() does not check argument type before attempting to read() or write()

[Serhiy Storchaka]

Serhiy Storchaka added the comment:

Builtin open() in Python 3 (and io.open() in Python 2.7) accept unicode strings, byte strings and integers as the first arguments (general path-like objects also are supported in Python 3.6, but it doesn't matter). bool is a subtype of int, and False is equal to integer 0. 0 is a file descriptor of sys.stdin.

>>> import sys
>>> sys.stdin.fileno()
0

Thus open(False) is equivalent to open(sys.stdin.fileno()). It creates a file object that wraps the file descriptor 0. This is legitimate operation.

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resolution:  -> not a bug
stage:  -> resolved
status: open -> closed

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Python tracker <report at bugs.python.org>
<http://bugs.python.org/issue29297>
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