[issue29259] Add tp_fastcall to PyTypeObject: support FASTCALL calling convention for all callable objects

STINNER Victor report at bugs.python.org
Fri Jan 13 10:08:22 EST 2017


STINNER Victor added the comment:

> * If a type only defines tp_fastcall: tp_fastcall is always use (tp_call uses the wrapper)
> 
> Is tp_call set to the wrapper rather then inheriting?

It is set to the wrapper. Defining tp_fastcall should work as defining tp_call: it should override the tp_call and tp_fastcall slots.


>  What if tp_call is defined in a superclass?

What is a superclass? Do you have an example?



> * If a type defines tp_call and tp_fastcall, PyObject_Call() uses tp_call whereas _PyObject_FastCallDict() uses tp_fastcall.
>
> I would consider this as a bug. It would be weird if different ways of calling cause executing different code.

It's a micro-optimization to avoid arguments unpacking/packing, conversions needed when you switch from the regular calling convention to the fast call convention, or the opposite.

I don't think that types defining tp_call and tp_fastcall will be common.


> What about dynamically changed Python types?

What do you mean? Do you have an example?


> What if you set or delete the __call__ attribute of Python class?

I don't know how these things work :-) Let me try on a patched Python (using tp_fastcall):

$ ./python
>>> class A:
...  def __call__(self): print("A")
... 
>>> a=A()
>>> a()
A

>>> A.__call__=lambda self: print("B!")
>>> a()
B!

>>> del A.__call__
>>> a()
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: 'A' object is not callable

It seems like "it just works", but I don't know how it works internally :-)

a() uses a dynamic lookup of a.__class__.__call__, no?

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<http://bugs.python.org/issue29259>
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