[issue16011] "in" should be consistent with return value of __contains__

[R. David Murray]

R. David Murray added the comment:

Eric: that is not precise enough, I'm afraid :)  See msg171093 for the correct documentation update.  Specifically, in returns True if __contains__ returns a true value, and False otherwise (not the difference in case, it matters).  There are more things than just None, False, and 0 that are false in Python.

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nosy: +r.david.murray

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