[issue30133] Strings that end with properly escaped backslashes cause error to be thrown in re.search/sub/etc. functions.

[Matthew Barnett]

Matthew Barnett added the comment:

Yes, the second argument is a replacement template, not a literal.

This issue does point out a different problem, though: re.escape will add backslashes that will then be treated as literals in the template, for example:

>>> re.sub(r'a', re.escape('(A)'), 'a')
'\\(A\\)'

re.escape doesn't always help.

The solution here is to pass a replacement function instead:

>>> re.sub(r'a', lambda m: '(A)', 'a')
'(A)'

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Python tracker <report at bugs.python.org>
<http://bugs.python.org/issue30133>
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