[issue26590] socket destructor: implement finalizer
STINNER Victor
report at bugs.python.org
Sat Mar 19 09:07:01 EDT 2016
STINNER Victor added the comment:
2016-03-19 11:05 GMT+01:00 Antoine Pitrou <report at bugs.python.org>:
> sock_finalize() is only called explicitly if there is a reference cycle. This is why sock_dealloc() has to call it.
I'm fine with keeping sock_dealloc() to call sock_finalize(), but I
would like to understand.
Example:
---
import socket
s=socket.socket()
s=None
---
With this code, sock_finalize() is called before sock_dealloc():
#0 sock_finalize (s=0x7ffff0730c28) at
/home/haypo/prog/python/default/Modules/socketmodule.c:4172
#1 0x00000000004d8f59 in PyObject_CallFinalizer (self=<socket at
remote 0x7ffff0730c28>) at Objects/object.c:294
#2 0x00000000004d8fcd in PyObject_CallFinalizerFromDealloc
(self=<socket at remote 0x7ffff0730c28>) at Objects/object.c:311
#3 0x00000000004f2c8f in subtype_dealloc (self=<socket at remote
0x7ffff0730c28>) at Objects/typeobject.c:1154
#4 0x00000000004dc8ae in _Py_Dealloc (op=<socket at remote
0x7ffff0730c28>) at Objects/object.c:1783
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<http://bugs.python.org/issue26590>
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