[issue24586] Operator precedence for 1<-1==0

[R. David Murray]

R. David Murray added the comment:

You missed the sentence just before the table that mentions that comparisons support chaining (see https://docs.python.org/3/reference/expressions.html#not-in).  1<-1==0 is actually equivalent to (1<-1) and (1==0), which is False.

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nosy: +r.david.murray
resolution:  -> not a bug
stage:  -> resolved
status: open -> closed

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