[issue24887] Sqlite3 has no option to provide open flags
Gerhard Häring
report at bugs.python.org
Wed Aug 19 11:50:43 CEST 2015
Gerhard Häring added the comment:
It requires switch to the v2 open function of the SQLite C API. While we're at it, we can also enable URI filenames.
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assignee: -> ghaering
nosy: +ghaering
versions: +Python 3.6 -Python 3.4
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